Now, we can calculate the work done:

where $W$ is the net work done and $\Delta KE$ is the change in kinetic energy. Let's consider some problems and their solutions:

A force of 10 N is applied to an object, causing it to move 5 m in the direction of the force. Calculate the work done.

where $v = 0$ (final velocity), $u = 4$ m/s (initial velocity), $a = -\frac{5}{2}$ m/s$^2$ (acceleration), and $s$ is the displacement.